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Page Title: Reactor Power Calculation
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Reaction Rates
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Nuclear Physics and Reactor Theory Volume 1 of 2
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Relationship Between Neutron Flux and Reactor Power

Rf N f f Rf N 1.29  x  1012 fissions cm3   sec 1  x  1020atoms cm3 3  x  1013 neutrons cm2   sec 4.3  x  1022  cm2 1  barn 1  x  1024  cm2 430  barns 1  watt 1  erg 1  x  107  watt  sec 1  MeV 1.602  x  106erg 1  fission 200  MeV 3.12  x  1010fissions second REACTION RATES DOE-HDBK-1019/1-93 Reactor Theory (Neutron Characteristics) NP-02 Page 20 Rev. 0 Step 2: To find the microscopic cross section, replace with (N x ) and solve f f for . f Reactor Power Calculation Multiplying the reaction rate per unit volume by the total volume of the core results in the total number of reactions occurring in the core per unit time.  If the amount of energy involved in each reaction were known, it would be possible to determine the rate of energy release (power) due to a certain reaction. In a reactor where the average energy per fission is 200 MeV, it is possible to determine the number  of  fissions  per  second  that  are  necessary  to  produce  one  watt  of  power  using  the following conversion factors. 1 fission = 200 MeV 1 MeV = 1.602 x 10    ergs -6 1 erg = 1 x 10    watt-sec -7 This is equivalent to stating that 3.12 x 10    fissions release 1 watt-second of energy. 10

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