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Page Title: Figure 2-3. Pascal's Law
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Mechanical Advantage.
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TM-1-1500-204-23-2 General Aircraft Maintenance (Pneudraulics Maintenance and Practices) Volume 2 Manual
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Uses of Hydraulic Systems in Army Aircraft.

TM 1-1500-204-23-2 Figure  2-3.  Pascal's Law (1) Principle.  In hydraulics, mechanical advantage can be explained as the ratio between two pistons with regard to the factors of area and force.  In figure 2-4, you see a graphic illustration of this principle.  Note the differences in  the  areas  of  the  small  and  large  pistons.    This  difference  in  size  is  the  means  by  which  mechanical  advantage  is obtained when a 50-pound force is applied to the small pistons, the fluid pressure shows 25 psi on the gauge, but 25 psi acting on the large piston gives an upward force of 250 pounds.  This gain in force (from 50 pounds to 250 pounds) is attained by increasing the surface area of the output piston.  It is important to note that this 5-to-1 ratio does not change if the pounds per square inch change. If, for example, the input force were limited to 20 psi or raised to 30 psi, the forces involved would obviously change but the ratio between the forces would still be 5 to 1. (2) Application.  An example of how to apply mechanical advantage is shown in figure 2-5.  Here we want to find just how big the large piston must be to raise an 800-pound weight.  Let us assume that we must raise the 800- pound weight by applying a 40-pound force to the 4-square-inch piston. The mechanical advantage in this case is 20-800 pounds divided by 40 pounds and is expressed as the ratio 20 1.  Multiplying 20 times 4 square inches (area of the small piston), we find that the area of the large piston should be 80 square inches.  Mechanical advantage also applies to the distance  the  piston  moves,  or  length  of  stroke.    Assuming  that  the  large  piston  must  move  10  inches,  multiplying  this factor by 20 gives 200 inches as the length of stroke for the small piston.  Of course, it would not be feasible for the small piston  to  move  that  far  on  a  single  stroke.    Therefore,  the  small  piston  must  move  through  a  series  of  short  repeated strokes. 2-3

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