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Page Title:
Solving Normality Problems (cont) |
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  Express the desired volume in liters.
1L
250 mL X --------= 0.250 L
1000 mL
Concentration is an expression of the relative amounts of solute and solvent
present, a ratio. Express the equivalents per liter and simplify the expression.
2.951 Eq
----------= 11.8 Eq/L
0.250 L
d. Example. What is the maximum volume of Na2CO3 solution that can be
prepared from 106.0 grams of Na2CO3 if the desired concentration of solution is 0.500
Eq/L?
Solution. Read the problem carefully and determine the desired quantity.
Volume in liters.
Determine the GEW of the compound.
Na2CO3
Na 23.0 X 2 = 46.0
C 12.0 X 1 = 12.0
O 16.0 X 3 = + 48.0
106.0 g/mol
106.0 g
mol
-------- X -------- = 53.00 g/Eq
mol
2 Eq
Calculate the grams per liter by multiplying the equivalent per liter
concentration times the grams per equivalent.
0.500 Eq
53.00 g
----------X --------= 26.5 g/L
L
Eq
MD0837
4-7
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